PREPARATION OF IODOFORM FROM ETHANOL WITH MELTING POINT AND PURIFICATION WITH MELTING POINT AND PURIFICATION

PREPARATION OF IODOFORM FROM ETHANOL

PREPARATION OF IODOFORM FROM ETHANOL WITH MELTING POINT AND PURIFICATION WITH MELTING POINT AND PURIFICATION 

REQUIREMENTS:

Apparatus:                                                                                     

Beakers, Funnel, Test tubes, Balance, Spatula, Water bath, Stirrer, Filter paper, etc

Chemicals:

                        Ethanol …………….………………………….. 20ml

                        Sodium carbonate …………………………….. 40gm

                        Iodine …………………………………………. 03gm

                        Distilled water ………………………...………… Q.S

THEORY:

Chemical Properties yellow solid with a characteristic pungent.

General Description Bright yellow or yellow powder or crystals. Penetrating odor. Unctuous touch.

Air & Water Reactions Insoluble in water.

Reactivity: Iodoform decomposes at high temperatures. Decomposes slowly in light at room temperature. Reacts violently with lithium. It is incompatible with mercuric oxide, calomel, silver nitrate, tannin, and balsam Peru. It is also incompatible with strong bases, strong oxidizing agents, and magnesium. Vigorous reactions occur with acetone in the presence of solid potassium hydroxide or calcium hydroxide, hexamethylenetetramine at 352° F, mercury(I) fluoride and finely divided reduced silver.

Fire Hazard Literature sources indicate that Iodoform is nonflammable

PROCEDURE:

1)      Sodium carbonate was taken in a beaker and sufficient water was added to dissolve it completely. It was then filtered.

2)      Then I added ethanol in it and it was warmed at 70-80 ^oC in a water bath.

3)      Then iodine was added with continuous stirring until completely dissolved.

4)      The yellow precipitate was observed after some time.

5)       Filtered and thus obtained residue on the filter paper.

6)      Then I weighed and determined the percent (%) yield.

CALCULATIONS AND RESULT

     Reaction:

2C­­₂H₅OH + 8I₂ + Na₂CO₃ + H₂O ……………….. 2 CHI₃ + 2HCOONa + CO₂ + 10HI

ACTUAL YIELD OF IODOFORM

     

      Iodine:

Molecular weight of iodine =           gm

4 moles of iodine used =

                                     =                  gm

Mass of iodine taken =                    gm

    

   Iodoform:

Molecular weight of iodoform =               gm

1 mole of iodoform produced =               gm

Mass of iodoform obtained (Actual yield) =           gm

THEORETICAL YIELD OF IODOFORM

         gm of iodine produces =           gm of iodoform

         gm of iodine produces      =  ×

                                               

                                              =           gm of iodoform

So,

Percentage yield =  Actual yield  × 100

                             Theoretical yield

                            =          ×100

                                  

                            =              %

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